\(\left \{ {{7*x - 3*y=25} \atop {2*x + 5*y=95}} \right.\)
\(\left \{ {{7x - 3y=25}(I) \atop {2x + 5y=95}(II)} \right.\)
\(\left \{ {{7x - 3y=25}simplify*(5) \atop {2x + 5y=95}simplify*(3)} \right.\)
\(\left \{ {{35x - \diagup\!\!\!\! 15 y=125} \atop {6x + \diagup\!\!\!\! 15y=285}} \right.\)
\(\left \{ {{35x =125} \atop {6x =285}} \right.\)
\(41x = 410\)
\(\boxed{x=10}\)
Replace the value of "x" in the second equation (II) to find the value of "y", thus:
\(2x + 5y=95\)
\(2*(10)+5y = 95\)
\(20+5y=95\)
\(5y=95-20\)
\(5y=75\)
\(y = \frac{75}{5}\)
\(\boxed{y=15}\)
The numbers (10,15)
