Answer:
Area of of the doghouse which is in the shape of right trapezoid is 66.5 square feet.
Step-by-step explanation:
Consider a right trapezoid with top side AB is 7 feet and height AD is 7 feet. The bottom side DC is extended to the right with 5 more feet.that is (7+5) 12 feet.
We have to find the area of the doghouse which is in the shape of right trapezoid .
\(\text{Area of trapezoid}=\frac{1}{2}\times (\text{sum of parallel sides})\times {\text{(Height)}}\)
that is,
\(\text{Area of trapezoid}=\frac{1}{2}\times (AB+DC)\times (AD)\)
Substitute the values, we get,
\(\text{Area of trapezoid}=\frac{1}{2}\times (7+12)\times 7\)
\(\Rightarrow \text{Area of trapezoid}=\frac{1}{2}\times 19\times 7\)
\(\Rightarrow \text{Area of trapezoid}=\frac{1}{2}\times 133\)
\(\Rightarrow \text{Area of trapezoid}=66.5\)
Hence, Area of of the doghouse which is in the shape of right trapezoid is 66.5 square feet.
