A 0.40 kg toy car moves at constant acceleration of 2.3 m/s2. determine the net applied force that is responsible for that acceleration.
Answer:
F = 0.92 N
Explanation:
It is given that,
Mass of the toy car, m = 0.4 kg
Acceleration of the car, \(a=2.3\ m/s^2\)
Let F is the net force applied to the to the toy car. It is equal to the product of mass and acceleration. Its formula is given by :
\(F=m\times a\)
\(F=0.4\ kg\times 2.3\ m/s^2\)
F = 0.92 N
So, the net applied force that is responsible for that acceleration is 0.92 N. Hence, this is the required solution.