remember some basic rules
\(\frac{x^m}{x^n}=x^{m-n}\)
and
\(x^ \frac{m}{n}= \sqrt[n]{x^m}\)
so
\(\frac{x^\frac{1}{2}}{x^\frac{2}{7}}=x^{\frac{1}{2}-\frac{2}{7}}\)
1/2-2/7=
7/14-4/14=
3/14
\(x^{\frac{1}{2}-\frac{2}{7}}=x^{\frac{3}{14}}\)
\(x^ \frac{3}{14}= \sqrt[14]{x^3}\)
