The total weight of 1 load of bricks and 3 loads of sticks : \(\large{\boxed{321.25\:kg}}}\)
Further Explanation
One variable linear equation is an equation that has a variable and the exponent number is one.
Can be stated in the form:
\(\large{\boxed{\bold{ax=b}}\)
or
ax + b = c, where a, b, and c are constants, x is a variable
Whereas the two-variable linear equation is a linear equation that has 2 variables and the exponent is one
Can be stated in the form:
\(\large{\boxed{\bold{ax+bx=c}}}\)
x, y = variable
In the statement of the task:
a load of bricks is twice as heavy as a load of sticks.
If we translate this sentence into equation, :
B = 2S ( B = bricks, S = sticks) ---> equation 1
the total weight of 4 loads of bricks and 4 loads of sticks is 771 kilograms.
If we translate this sentence into equation, :
4B + 4S = 771 kg ---> equation 2
This equation belongs to One variable linear equation because there is two variable = B&S and the exponent number is one
The solution is :
we put equation 1 in equation 2, become :
8S + 4S = 771 kg
12S = 771 kg
\(\displaystyle S=\frac{771}{12}\)
\(\large{\boxed{S=64.25\:kg}}\)
from equation 1 :
B = 2 x S
B = 2 x 64.25 kg
B = \(\large{\boxed{128.5\:kg}}\)
the total weight of 1 load of bricks and 3 loads of sticks
If we translate this sentence into equation,
B + 3S = ?
we enter the values of B and S from the results of the equation above
= 128.5 kg + 3(62.25 kg)
= 128.5 kg + 192.75 kg
= \(\large{\boxed{\boxed{\bold{321.25\:kg}}}\)
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Keywords : one variable, linear equation , two variable, bricks, sticks
