The length of a straight line ABC is 5m. If AB:BC= 2:5, find the length of AB
AB/BC = 2/5
AC=5
AB/(AB+BC)=2/(2+5)
AB/AC=2/7
AB/5=2/7
AB=10/7=1.4286 m
Answer:
\(\frac{10}{7}\approx 1.43\text{ m}\).
Step-by-step explanation:
We have been given the length of a straight line ABC is 5 m. We are asked to find the length of AB, when \(AB:BC=2:5\).
We can represent our given ration as:
\(\frac{AB}{BC}=\frac{2}{5}\)
We can write above ratio in terms of AC as:
\(\frac{AB}{AB+BC}=\frac{2}{2+5}\)
\(\frac{AB}{AC}=\frac{2}{2+5}\)
Upon substituting \(AC=5\), we will get:
\(\frac{AB}{5}=\frac{2}{7}\)
\(\frac{AB}{5}*5=\frac{2}{7}*5\)
\(AB=\frac{2*5}{7}\)
\(AB=\frac{10}{7}=1.42857\)
Therefore, the length of AB is \(\frac{10}{7}\approx 1.43\text{ m}\).