Verified Answer :

Given two points A(x₁,y₁) and B(x₂,y₂) the distance betwen these points will be:
dist(A,B)=√[(x₂-x₁)²+(y₂-y₁)²].

We have these points: A(0,0) and B(6,3); its distance will be:

dist(A,B)=√[(6-0)²+(3-0)²]
=√(6²+3²)
=√(36+9)
=√45 ≈ 6.71

Answer:  D.    6.71 units.

MrRoyal

The length of segment AB is 6.71 units

How to determine the length?

The given parameters are:

A = (0,0) and B = (6,3)

The length AB is calculated using:

\(AB = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}\)

Substitute known values

\(AB = \sqrt{(6 -0)^2 + (3-0)^2}\)

Evaluate the sum of exponents

\(AB = \sqrt{45}\)

Evaluate the square root

AB = 6.71

Hence, the length of AB is 6.71 units

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