(y+3)(y^2-3y+9 what is the product?
=(y+3)(y^2+−3y+9)=(y)(y^2)+(y)(−3y)+(y)(9)+(3)(y^2)+(3)(−3y)+(3)(9)=y^3−3y^2+9y+3y^2−9y+27Answer:=y3+27