Protons, Neutrons, Electrons for isotopes: Zirconium-90 and Antimony-123?
Data:
z = p = e
Using:
Zirconium \(Zr^{90}\)
Atomic Mass (A) = 90
Atomic number (z) = 40
Neutron number (n) = ?
A = z + n
90 = 40 + n
n = 90 - 40
n = 50
Soon (Zirconium)
z = p = e
40 = 40 = 40
Protons (p) = 40
neutrons (n) = 50
Electrons (e) = 40
----------------------------------------------------
Using:
Antimony \(Sb^{123}\)
Atomic Mass (A) = 123
Atomic number (z) = 51
Neutron number (n) = ?
A = z + n
123 = 51 + n
n = 123 - 51
n = 72
Soon (Antimony)
z = p = e
51 = 51 = 51
Protons (p) = 51
neutrons (n) = 72
Electrons (e) = 51
Atomic number=40
Atomic mass=91 Of Zr
Protons and neutrons are the same as atomic number so:
Protons=40
neutrons=91-40=51
Electron=40
Atomic number=51
Atomic mass=121.763 approximately 122 of SN
Protons=51
neutrons=122-51=71
electrons=51