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tepAveierTheholmo tepAveierTheholmo
  • 07-01-2017
  • Physics
Answered

A wave travels a distance of 60cm in 3s. The distance blw successive crests of thd wave is 4cm. What is the frequency?

Verified Answer :

dexteright02
dexteright02 dexteright02
  • 07-01-2017

Data:
ΔS = 60cm
Δt = 3s
Vm = ?

Vm = ΔS/Δt 
\(Vm = \frac{60}{3}\)
\(Vm = 20cm/s\)

We have:

Vm = v
ΔS = λ
Δt = T

\(v = \frac{\lambda}{T}\)
\(20 = \frac{\lambda}{4}\)
\(\lambda = 20*4\)
\(\lambda = 80cm\)

Soon:

\(v = \lambda*f\)
\(20 = 80*f\)
\(80f = 20\)
\(f = \frac{20}{80} simplify( \frac{\div20}{\div20} )= \frac{1}{4}\)
\(\boxed{f = 0,25Hz}\)


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