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hamzasy hamzasy
  • 06-01-2017
  • Mathematics
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MissPhiladelphia
MissPhiladelphia MissPhiladelphia
  • 10-01-2017

Let n be the number of sides of a polygon.

To solve for the sum of the interior angles:
(n-2) x 180°

To solve for the measure of each interior angle of the polygon
[(n-2) x 180°] / n

To solve for the measure of each exterior angle:
360° / n

The sum of the exterior angles is always 360°

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