daisyneadle
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Captain Jessica has a ship, the H.M.S. Khan. The ship is two furlongs from the dread pirate Luis and his merciless band of thieves. The Captain has probability 4/9 of hitting the pirate ship. The pirate only has one good eye, so he hits the Captain's ship with probability 1/4 ​​.If both fire their cannons at the same time, what is the probability that both the pirate and the Captain hit each other's ships?

Verified Answer :

Answer: Probability that both the pirate and the Captain hit each other's ships is \(\frac{1}{9}\)

Step-by-step explanation:

since we have given that

Probability that the captain hits the pirate ship is given by

\(\frac{4}{9}\)

Probability that the pirate hits the Captains's ship is given by

\(\frac{1}{4}\)

So, we have to find the "Probability that both the pirate and the Captain hit each other's ship"  is given by

\(P(\text{Captain hits})\times P(\text{ Pirates hit})\\\\=\frac{4}{9}\times \frac{1}{4}\\\\=\frac{1}{9}\)

Hence, probability that both the pirate and the Captain hit each other's ships is \(\frac{1}{9}\)

dubeyshailja64

The probability that both the pirate and the Captain hit each other's ships is \(\dfrac{1}{9}\). This can be calculated by calculating the joint probability of both events.

What is joint probability?

A joint probability is a probability that two events will occur together and at the same time. Simply it is the probability that A occurs at the same time when B occurs. It can be calculated as:

\(P(A and B) = P(A) * P(B)\), where P(A and B) is the joint probability of A and B occurring together, P(A) is the probability of A, and P(B) is the probability of B.

Given:

The probability of Captain hitting the pirate ship is  \(\dfrac{4}{9}\)

The probability of pirate hitting the Captain's ship is \(\dfrac{1}{4}\).

Therefore the joint probability will be:

\(\dfrac{4}{9}\times\dfrac{1}{4} = \dfrac{1}{9}\)

Learn more about Joint probability here:

https://brainly.com/question/14238558

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