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Given the following sequence, find the 15th term: 3, 1, –1, –3, –5, . . .

A–28
B–25
C–33
D–21

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L0rdPh03nix

its a arithmetic progression with d = 1-3 = -1-1= -2
hence a15 = a1 + 14d
hence a15 = 3 + 14(-2) = -25 
here a1 represent first term , d represent common difference

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