the distance between the points (x1,y1) and (x2,y2) is
D=\(\sqrt{(x2-x1)^2+(y2-y1)^2}\)
given
(-3,3) and (3,-3)
D=\(\sqrt{(3-(-3))^2+(-3-3)^2}\)
D=\(\sqrt{(3+3)^2+(-6)^2}\)
D=\(\sqrt{(6)^2+36}\)
D=\(\sqrt{36+36}\)
D=√72
D=(√36)(√2)
D=6√2
the disatnce is 6√2
about 8.48
answer is A
