You just got a free ticket for a boat ride, and you can bring along 2 friends! Unfortunately, you have 5 friends who want to come along. How many different groups of friends could you take with you?
There are 10 different groups of friends could you take with you
Given
You just got a free ticket for a boat ride, and you can bring along 2 friends.
Unfortunately, you have 5 friends who want to come along.
The combination is a process of selection of elements from a set of elements in which the order of selection does not matter.
The combination is determined by the following formula;
\(\rm ^np_r = \dfrac{n!}{(n-r)! \times r!}\)
Where P is the number of groups.
n is the number of people to choose from.
r is the number of people that we choose.
Therefore,
The number of ways groups of friends could you take with you is;
\(\rm ^np_r = \dfrac{n!}{(n-r)! \times r!}\\\\\rm ^5p_2 = \dfrac{5!}{(5-2)! \times 2!}\\\\\rm ^5p_2 = \dfrac{5!}{3! \times 2!}\\\\\rm ^5p_2 = \dfrac{5 \times 4 \times 3\times 2\times 1}{2\times 1 \times 3\times 2\times 1}}\\\\ ^5p_2 = \dfrac{20}{2}\\\\ ^5p_2 = 10\)
Hence, there are 10 different groups of friends could you take with you.
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