4x^1/2 to radical form
\(x^ \frac{m}{n}= \sqrt[n]{x^m}\)pemdas, so exponent first before multiply4(x^1/2)=4x^2this is different from(4x)^1/2so\(x^ \frac{1}{2}= \sqrt[2]{x^1}\)times that by 44√x
4√x will be the answer.Hope this helped, and please mark brainliest! :)