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praolg
praolg praolg
  • 04-01-2017
  • Mathematics
Answered

rozwiąż równanie kwadratowe: 3/4 y^2 +9=y/2+(y-3)^2

Verified Answer :

LammettHash
LammettHash LammettHash
  • 04-01-2017

Najpierw rozszerz po prawej strony równania.

\(\dfrac34y^2+9=\dfrac y2+(y-3)^2\implies\dfrac34y^2+9=\dfrac y2+y^2-6y+9\)

Przenieść wszystko na jedną stronę i uproszcz.

\(\dfrac{y^2}4-\dfrac{11y}2=0\)

Rozkładaj lewą stronę na czynniki.

\(\dfrac14y(y-22)=0\)

Są dwa rozwiązania,

\(y=0\text{ i }y=22\)

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