see the attached figure to better understand the problem
we know that
The volume of the cone is equal to
\(V=\frac{1}{3} \pi r^{2} h\)
in this problem
\(r=\frac{6}{2} =3\ ft\\ \\ h=15\ ft\)
Substitute the values in the formula above
\(V=\frac{1}{3}* \pi* 3^{2}* 15\\ \\ V=45\pi \ ft^{3}\)
therefore
the answer is
The volume of the nose cone is \(45\pi \ ft^{3}\)
