What is the value of 2x{6+[12/(3+1)}-1
What is the value of 2x{6+[12/(3+1)}-1
Start with innermost parenthesis-(3+1)=4
then the next-12/4=3
then add 6=9
then multiply by the 2=18
then subtract 1
=17
The value of an expression is calculated by simplifying the expression.
The value of the expression is 17
The expression is given as:
\(\mathbf{2 \times \{6+[12 \div (3+1)\}-1}\)
Simplify 3 + 1
\(\mathbf{2 \times \{6+[12 \div (3+1)\}-1 = 2 \times \{6+[12 \div 4\}-1}\)
Divide
\(\mathbf{2 \times \{6+[12 \div (3+1)\}-1 = 2 \times \{6+[3\}-1}\)
Remove square bracket
\(\mathbf{2 \times \{6+[12 \div (3+1)\}-1 = 2 \times \{6+3\}-1}\)
Add
\(\mathbf{2 \times \{6+[12 \div (3+1)\}-1 = 2 \times \{9\}-1}\)
Remove curly bracket
\(\mathbf{2 \times \{6+[12 \div (3+1)\}-1 = 2 \times 9-1}\)
Multiply
\(\mathbf{2 \times \{6+[12 \div (3+1)\}-1 = 18-1}\)
Subtract
\(\mathbf{2 \times \{6+[12 \div (3+1)\}-1 = 17}\)
Hence, the value of the expression is 17
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