Verified Answer :

LammettHash

If \(x\) is the first integer, then the next two are \(x+2\) and \(x+4\).

If the product of the first and second are greater than the third integer by 8, that means you have the following equation:

\(x(x+2)=(x+4)+8\implies x^2+x-12=(x-3)(x+4)=0\implies x=3\text{ or }x=-4\)

Ignore \(x=-4\) since it's an even integer.

Check that \(x=3\) is correct. The next two odd integers would be \(5\) and \(7\). You have

\(3\times5=15=7+8\)

so this is correct.

abidemiokin

They consists of several equations with unknown. The three numbers will be 3, 5 and 7

System of equations

They consists of several equations with unknown

Let the first three consecutive odd integers be x, x + 2 and x+ 4

If the product of the first and the second exceeds the third by 8, hence;

x(x+2) = x + 4 + 8

x² +2x = x + 12

x² + x - 12 =0

Factorize

x² + 4x -3x - 12 =0

x(x+4) - 3(x+4) = 0

(x-3)(x+4) = 0
x = 3 and -4

The three numbers will be 3, 5 and 7

Learn more on equations here: https://brainly.com/question/13763238

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