Keywords
quadratic equation, discriminant, complex roots, real roots
we know that
The formula to calculate the roots of the quadratic equation of the form \(ax^{2} +bx+c=0\) is equal to
\(x=\frac{-b(+/-)\sqrt{b^{2}-4ac}}{2a}\)
where
The discriminant of the quadratic equation is equal to
\(b^{2}-4ac\)
if \((b^{2}-4ac)> 0\) ----> the quadratic equation has two real roots
if \((b^{2}-4ac)=0\) ----> the quadratic equation has one real root
if \((b^{2}-4ac)< 0\) ----> the quadratic equation has two complex roots
in this problem we have that
the discriminant is equal to \(-8\)
so
the quadratic equation has two complex roots
therefore
the answer is the option A
There are two complex roots
