Answered

Charles Law


A balloon of helium was put in the freezer at -23°C. Its volume at this temperature was 2.5 liters. It was removed from the freezer. Eventually, it reached a temperature of 177°C. What would its volume be at this temperature? (Neglect any force used to stretch the rubber balloon.) HELP ASAP

A1.4
B45000
C4.5
D0.22

Verified Answer :

Antdog159

The answer can't be A because it is the amount in liters and D is less than the average B only gives the full value non right of the decimal so the answer is C

Answer : The volume at \(177^oC\) will be, (C) 4.5 L

Explanation :

Charles' Law : It is defined as the volume of gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

\(V\propto T\)

or,

\(\frac{V_1}{V_2}=\frac{T_1}{T_2}\)

where,

\(V_1\) = initial volume of gas = 2.5 L

\(V_2\) = final volume of gas = ?

\(T_1\) = initial temperature of gas = \(-23^oC=273+(-23)=250K\)

\(T_2\) = final temperature of gas = \(177^oC=273+177=450K\)

Now put all the given values in the above formula, we get the final volume of the gas.

\(\frac{2.5L}{V_2}=\frac{250K}{450K}\)

\(V_2=4.5L\)

Therefore, the volume at \(177^oC\) will be, (C) 4.5 L

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