If \(x\) is one of the component integers, then the next consecutive integer is \(x+1\), the following one is \(x+2\) and so on.
This means the sum can be written as
\(x+(x+1)+(x+2)+(x+3)=114\)
Solving for \(x\), you find that \(x=27\), so the integers are \(27,28,29,30\).
