Following are the calculation for the expected age:
Given:
\(\to \bold{\frac{1}{4}= 5\ years}\\\\\to \bold{\frac{1}{2}= 6\ years}\\\\\to \bold{\frac{1}{8}= 7\ years}\\\\\to \bold{\frac{1}{8}= 5\ years}\\\\\)
To find:
expected age=?
Solution:
\(\to \bold{\frac{1}{4}= 5\ years}\\\\\to \bold{\frac{1}{2}= 6\ years}\\\\\to \bold{\frac{1}{8}= 7\ years}\\\\\to \bold{\frac{1}{8}= 5\ years}\\\\\)
Adding the ages:
\(\to \bold{\frac{1}{4} \times 5 +\frac{1}{2} \times 6 +\frac{1}{8}\times 7+ \frac{1}{8}\times 5}\\\\\to \bold{\frac{5}{4} +\frac{6}{2} +\frac{7}{8}+ \frac{5}{8}}\\\\\to \bold{ 1.25 + 3 +0.875+ 0.625}\\\\\to \bold{5.75 \approx 6}\)
Therefore, the answer is "6"
Learn more:
brainly.com/question/12147752
