well, find the legnth and width because lenth times width =area
we just need to find 2 differnd distances
the distance between 2 points, (x1,y1) and (x2,y2) is
\(D= \sqrt{(x2-x1)^2+(y2-y1)^2}\)
let's find distance between (-6,3) and (-3,6)
\(D= \sqrt{(-3-(-6))^2+(6-3)^2}\)=√18=3√2
the other one
from (-3,6) to (1,2)
\(D= \sqrt{(1-(-3))^2+(2-6)^2}\)=√32=4√2
area=legnth times width
legnth=4√2
width=3√2
area=4√3 times 3√2=12*2=24
the area is 24
