The equation of a line starting from two points is:
\(y-y_1=\frac{y_2-y_1}{x_2-x_1} \cdot (x-x_1)\)
From the first point you get: x1 = -1, y1 = -2
From the second point you get: x2 = 3, y2 = 10
Replace x1, y1, x2, y2 in the equation of the line and you get:
\(y+2=\frac{10+2}{3+1} \cdot (x+1)\)
\(y+2=\frac{12}{4} \cdot (x+1)\)
\(y+2=3 \cdot (x+1)\)
From this you get the equation of your line:
\(y(x)=3x+1\)
