use substitution to solve s+a=4 and 35+5a=2550
35+5(4-s)=255035+20-5s=255055-5s=2550-55 -55-5s = 2495s = - 499-499 + a = 4+499 +499a = 503
s + a = 4 35 + 5a = 2550From the second equation:35 + 5a = 25505a = 2550 - 355a = 2515a = 2515/5 a = 503From s + a = 4s + 503 =4s = 4 - 503s = -499Therefore a = 503, s = -499
