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The fulcrum of a first-class lever divides its 9.0 m arm into two sections—a 6.0 m arm and a 3.0 m arm. You place a rock weighing 98.1 N on the 3.0 m end. How much force do you need to exert on the 6.0 end to balance the lever?


a)49 N

b)200 N

c)880 N

d)1,800 N

Verified Answer :

For balancing the lever, force on both the sides shall be equal. so,
Force on 3 m end = m × a = 3 × 98.1 = 294.3

Now, on 6 m end, it would be: = 294.3/6 = 49.05
After rounding-off to the nearest hundredth value, it would be: 49 N

Finally, Option A would be your correct answer.

Hope this helps!

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