a 40 kilogramstudent runs up a staircase to a floor that is 5.0 meters higher than her starting point in 7.0 seconds. the student's power output is
When she reaches the top, she has more potential energy than she had at the bottom.
Potential energy = (mass) x (gravity) x (height)
= (40 kg) x (9.8 m/s²) x (5 m)
= 1,960 more joules .
Power = (energy) / (time)
= (1,960 joules) / (7 seconds)
= 280 watts
(about 0.375 horsepower)
Power is measured in Joule/s or Watt. The power output of the girl is 280 W.
It can be defined as the ratio of energy to time. The formula of power is,
\(P = \dfrac Et\).................1
Where,
\(E\) - Energy
\(t\)= time = 7 s.
First, calculate the potential energy of the student,
\(PE = mgh\).............2
Where,
\(m\) - mass = 40 kg
\(g\) - gravitational acceleration = 9.8 m/s²
\(h\) - height = 5 m
Put the values in equation 2,
\(PE = 40 \times 9.8 \times 5 \\PE = 1,960 \rm \ J\)
From equation 1,
\(P= \dfrac {1,960 }7\\\\P = 280 \rm \ W\)
Therefore, the power output of the girl is 280 W.
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