Verified Answer :

arthurpdc

The conjugate of a complex number \(z=a+bi~(a,b\in\mathbb{R})\) is \(\overline{z}=a-bi\). So, for the complex\(z=4-3i\), the conjugate is \(\overline{z}=4+3i\).

calculista

Answer:

\(4+3i\)

Step-by-step explanation:

we know that

To find the conjugate complex of a complex number, simply change the sign of the imaginary part of the complex number

In this problem we have

\(4-3i\)

so

the complex conjugate is equal to

\(4+3i\)

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