\(\lim_{x \to \infty} \frac{|x-2|}{x-2}\)
as approaches 2-
that '-' after the 2 means as it approaches from the left
ok
from the left, it is like from 1 to 2
as it approaches from the left, it is \(\frac{-1(x-2)}{x-2}\)
it is negative since when the value of x is smaller than 2, the value of x-2 is negative so then the absolute value is making it positive, to do that, we multiply it by -1
therefor
\(\frac{-1(x-2)}{x-2}\) or -1
it approaches -1
