3y+2=5(y-6) please help :)
In this problem, y = 16!
Y = 16 =3y+2=5(y−6)=3y+2=5y−30=3y+2−5y=5y−30−5y=−2y+2=−30=−2y+2−2=−30−2=−2y=−32=−2y−2=−32−2y=16