Answer: (4,1)
Step-by-step explanation:
The given system of equations :
\(3x+4y=16.............................(1)\\\\-4x-3y=-19...........................(2)\)
Multiplying equation (1) by 4 and equation (2) by 3 we get,
\(12x+16y=64.............................(3)\\\\-12x-9y=-57...........................(4)\)
Add (3) and (4), we get
\(7y=7\\\\\Rightarrow\ y=1\)
Substitute y=1 in (1), we get
\(3x+4(1)=16\\\\\Rightarrow\ 3x=12\\\\\Rightarrow x=4\)
Hence, the solution of the given system = (4,1)
