Answer:
\(\% Cl=61.65\%\)
Explanation:
Hello,
In this case, chlorine's percent composition is given by the shown below formula:
\(\% Cl=\frac{n_{Cl}m_{Cl}}{M_{NaCl}}*100\%\)
Whereas \(n_{Cl}\) accounts for the number of chlorine atoms into the NaCl, \(m_{Cl}\) for chlorine's atomic mass and \(M_{NaCl}\) for sodium chloride's molar mass, therefore, the percent composition of chlorine turns out:
\(\% Cl=\frac{1*35.45}{58.45}*100\%=61.65\%\)
Best regards.
