Answer:
\(x=-\frac{3}{2}\)
Step-by-step explanation:
We have been given an equation \(\frac{1}{4}+\frac{1}{2}+x=-\frac{3}{4}\). We are asked to solve for x.
Let us make common denominator as:
\(\frac{1}{4}+\frac{1*2}{2*2}+x=-\frac{3}{4}\)
\(\frac{1}{4}+\frac{2}{4}+x=-\frac{3}{4}\)
Add numerators:
\(\frac{1+2}{4}+x=-\frac{3}{4}\)
\(\frac{3}{4}+x=-\frac{3}{4}\)
\(\frac{3}{4}-\frac{3}{4}+x=-\frac{3}{4}-\frac{3}{4}\)
\(x=\frac{-3-3}{4}\)
\(x=\frac{-6}{4}\)
\(x=-\frac{3}{2}\)
Therefore, the value of x is \(-\frac{3}{2}\).
