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Isoke is solving the quadratic equation by completing the square. 10x2 + 40x – 13 = 0        10x2 + 40x = 13         A(x2 + 4x) = 13 What is the value of A?

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10x^2+40=13


10 (x^2+4)=13



A=10

Answer:

 A = 10

Step-by-step explanation:

We have given that : A quadratic equation \(10x^2+40x-13=0\)

                                   another equation \(A(x^2+4x)=13\)

To find:  The value of A

Solution: Taking the quadratic equation  \(10x^2+40x-13=0\)

and try to reduce this equation in form of another equation

\(10x^2+40x-13=0\) ⇒ \(10(x^2+4x)=13\)

Comparing with another equation \(A(x^2+4x)=13\)

we get that 10 takes the place of A

which implies value of A = 10


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