lisapressley2001 lisapressley2001

01-01-2017
Mathematics

Answered

Solve using quadratic formula. 2x^2+6x+3=0

Verified Answer :

01-01-2017

\(x = \frac{-b +/- \sqrt{b^{2} -4ac} }{2a}\)

a = 2
b = 6
c = 3

\(x = \frac{-6 +/- \sqrt{6^{2} -4*2*3} }{2*2}\)

\(x = 0.634\) or \(x = -2.366\)

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