4(x-3)+7-10x=5 what is the value of x
\(4\cdot(x-3)+7-10x=5\\\\4\cdot x+4\cdot(-3)+7-10x=5\\\\4x-12+7-10x=5\\\\-6x-5=5\ \ \ \ /+5\\\\-6x-5+5=5+5\\\\-6x=10\ \ \ \ /:(-6)\\\\-6x:(-6)=10:(-6)\\\\x=-\frac{10}{6}\\\\x=-\frac{5}{3}\\\\x=-1\frac{2}{3}\)
