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A truck enters a stretch of road that drops 4 meters

in elevation for every 100 meters along the length of

the road. The road is at 1,300 meters elevation where

the truck entered, and the truck is traveling at

16 meters per second along the road. What is the

elevation of the road, in meters, at the point where

the truck passes t seconds after entering the road?

Verified Answer :

1300 - 0.64t Answer<

m = -4m/ 100m = -.04

1300 - .04 (16) (t)

Meters - .04 (Meters / sec.) (sec.)

Cricetus

The elevation of the road will be "1300-0.64t".

According to the question,

Speed of truck,

  • 16 m/s

Distance covered by truck in t seconds,

  • x = 16t

Drop of,

  • 4 m

Let,

  • Truck entered at x = 0.
  • Elevation or height be "y".

Now,

→ The drop per meter:

= \(\frac{4}{100}\)

→ The drop for 16t length:

= \(\frac{4\times 16t}{100}\)

= \(0.64 t\)

hence,

→ \(Elevation = Initial \ elevation - Drop\)

                   \(= 1300-0.64 t\)

Thus the above answer is right.

Learn more about elevation here:

https://brainly.com/question/20268108

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