Verified Answer :

simplified it is just 2 exponent x-4 exponent x-1 without the parenthesis.

reemmeber
\((x^m)^n=x^{mn}\)
and
\(x^{m+n}= (x^m)(x^n)\)

\(2^x-4^{x-1}\)
4=2²
\(2^x-(2^2)^{x-1}\)
\(2^x-2^{(2)(x-1)}\)
\(2^x-2^{2x-2}\)
\(2^x-(2^{2x})(2^-2)\)
\(2^x-((2^x)^2)(2^-2)\)
\(2^x-(2^x)(2^x)(2^-2)\)
(2^x)(1-2^{x-2})
not sure if what you were looking for