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The line with equation 4b + a = 0 coincides with the terminal side of an angle x in standard position in Quadrant IV.


What is sin x?


\[ -\frac{1}{4} \]

\[ \frac{\sqrt{17}}{17} \]

\[ \sqrt{17} \]

\[\frac{\sqrt[4]{17}}{17} \]

Verified Answer :

MissPhiladelphia

The equation of the line is
4b + a = 0

The slope of the line is
m = -1/4

With a rise of 1 and run of -4 which corresponds to a hypotenuse of
√(4² + (-1)²) = √17

Therefore, the sine of the angle is
sin θ = 1/√17

SenpaiTrill

Hello there.

The line with equation 4b + a = 0 coincides with the terminal side of an angle x in standard position in Quadrant IV. 

What is sin x?
\[ \sqrt{17} \]

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