substitute one by one and see which pair satisfy it.
(-1,3)
3=3(-1)
3=-3
it is not true,so not a solution.
(2,5)
5=3×1
5=3
it is not true so not asolution.
(1,3)
3=3×1
3=3
it is true so (1,3)is a solution.
(-2,-6)
-6=3×(-2)
-6=-6
which is true.
Hence (-2,-6) is also a solution.