Verified Answer :

apologiabiology

remember

\(x^ \frac{m}{n} = \sqrt[n]{x^m}\)
and
\((x^m)^n=x^{mn}\)
 so

\(x^ \frac{3}{5} = \sqrt[5]{4^3}\)
but wait, there's more

4=2², so

\(x^ \frac{3}{5} = \sqrt[5]{4^3} = \sqrt[5]{(2^2)^3} = \sqrt[5]{2^6}\)=
\(2^ \frac{6}{5}=(2^ \frac{5}{5})(2^ \frac{1}{5})=2 \sqrt[5]{2}\)

also, 4^3=64


so possible ones are
\(2^ \frac{6}{5}\)
\(\sqrt[5]{4^3}\)
\(\sqrt[5]{64}\)
\(2 \sqrt[5]{2}\)
of the ones listed, the 2nd and 3rd options are correct (\(\sqrt[5]{4^3}\) and \(\sqrt[5]{64}\))

bcalle

The 2nd and 3rd are correct

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