Verified Answer :

The answer is 17/33.

The repeating decimal \(0.5151....\) as a fully simplified fraction will be   \(\frac{17}{33}\).

What is repeating decimal ?

Repeating decimal or recurring decimal is decimal representation of a number whose digits are periodic and the infinitely repeated portion is not zero.

We have,

Repeating decimal \(0.5151.....\) .

Let,

\(x=0.51\)    \(..........(i)\)

As it have two decimal, so multiply on both sides by \(100\),

\(100x=51.51\)    \(..........(ii)\)

Now, subtract equation \((i)\) from equation \((ii)\),

\(100x-x=51.51-0.51\)

\(99x=51\)

\(x=\frac{51}{99}\)

Now, to simplify it more divide numerator and denominator from \(3\),

We get ,

\(x=\frac{17}{33}\)

So, the simplified fraction of the given  repeating decimal is \(\frac{17}{33}\).

Hence, we can say that the repeating decimal \(0.5151....\) as a fully simplified fraction will be   \(\frac{17}{33}\).

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