Consider that an = 4n-1 represents a sequence. what is the tenth term?n-1 is a exponent

geometric sequence since exponent
\(a_n=a_1r^{n-1}\)
a1=firs term
r=common ratio
n=which term

no first term given, or is there?
4^(n-1), first term is 1, common ratio is 4

just plug in 10 for n
\(a_{10}=(1)4^{10-1}\)
\(a_{10}=4^{9}\)
\(a_{10}=4^{9}\)
\(a_{10}=262144\)
tenth term is 262144

Answer Link

psm22415 psm22415 · Answer 2 · 2021-12-20T23:15:48-05:00

The tenth term n-1 is an exponent is 262144.

Given that,

Consider that an = 4n-1 represents a sequence.

We have to determine,

What is the tenth term n-1 is an exponent.

According to the question,

The geometric sequence is,

\(a_n = a \times n^{r-1}\)

Where, \(a_1\) = first term
, r =common ratio
, n = number of term.

An = 4n-1 represents a sequence.

The tenth term n-1 is an exponent is,

\(a_1_0 = 1\times 4^{10-1}\\\\a_1_0 = 1\times 4^{9}\\\\a_1_0 = 1\times 262144\\\\a_1_0 = 262144\\\)

Hence, The required tenth term n-1 is an exponent is 262144.

To know more about the Series click the link given below.

https://brainly.com/question/11234923