You are throwing darts at a dart board. You have a 1/ 6 chance of striking the bull's-eye each time you throw. If you throw 3 times, what is the probability that you will strike the bull's-eye all 3 times?

A5 /136

B1/ 216

C3/ 233

D1/ 100

Verified Answer :

B. 1/216

bc 1/61/61/6

Answer: B. \(\frac{1}{216}\)

Step-by-step explanation:

Given: The chances of striking the bull's-eye each time of throw =\frac{1}{6}

Since, if we throe dart on dart board , each event will be independent of the other.

Then, If we throw 3 times, what is the probability that we will strike the bull's-eye all 3 times is given by :-

\(\text{P(strike bull's-eye)}=\frac{1}{6}\times\frac{1}{6}\times\frac{1}{6}=\frac{1}{216}\)

Hence, the probability that we will strike the bull's-eye all 3 times is \(\frac{1}{216}\).