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Simplify (4xy)(2x2y)(3xy)3.


24x2y3


24x6y5


216x3y3


216x6y5



Simplify (4xy)(2x^2y)(3xy)^3.


24x^2y^3


24x^6y^5


216x^3y^3


216x^6y^5

Verified Answer :

The correct answer is 216x⁶y⁵.

Explanation:
The first thing we do is raise the last monomial to the third power.

(4xy)(2x²y)(3xy)³
=(4xy)(2x²y)(3³x³y³)
=4xy(2x²y)(27x³y³).

Now we can multiply the first two monomials. When we multiply powers with the same base, we add the exponents:
8x³y²(27x³y³).

We multiply these last two monomials, again adding the exponents:
216x⁶y⁵.

JeanaShupp

Answer:  \(216x^6y^5\)

Step-by-step explanation:

The product law of exponents are given as :-

\(a^m\times a^n=a^{m+n}\)

Given expression:-\((4xy)(2x^2y)(3xy)^3\)

Which can be written as

\((4xy)(2x^2y)(27x^3y^3)\\=4\cdot2\cdot27\cdot x^{1+2+3}y^{1+1+3}\\=216x^6y^5\)

hence the simplifies form of the given expression is  \(216x^6y^5\)

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