Using the distributive property to find the product (y – 4)(y2 + 4y + 16) results in a polynomial of the form y3 + 4y2 + ay – 4y2 – ay – 64. What is the value of a in the polynomial?

Verified Answer :

(y - 4)(y^2 + 4y + 16) = y^3 + 4y^2 + 16y - 4y^2 - 16y - 64

Therefore, a = 16.

For this case we have the following expression:


\((y - 4) (y ^ 2 + 4y + 16)\)

Using the distributive property, we have:

\(y (y ^ 2 + 4y + 16) -4 (y ^ 2 + 4y + 16)\)

Rewriting the expression we have:


\(y^ 3 + 4y ^ 2 + 16y - 4y ^ 2 - 16y - 64\)

Comparing with the given expression we have:

\(y ^ 3 + 4y ^ 2 + ay - 4y ^ 2 - ay - 64 = y ^ 3 + 4y ^ 2 + 16y - 4y ^ 2 - 16y - 64\)

From where we conclude that:

\(a = 16\)

Answer:

The value of a in the polynomial is:

\(a = 16\)