Using the distributive property to find the product (y – 4)(y2 + 4y + 16) results in a polynomial of the form y3 + 4y2 + ay – 4y2 – ay – 64. What is the value of a in the polynomial?
(y - 4)(y^2 + 4y + 16) = y^3 + 4y^2 + 16y - 4y^2 - 16y - 64
Therefore, a = 16.
For this case we have the following expression:
\((y - 4) (y ^ 2 + 4y + 16)\)
Using the distributive property, we have:
\(y (y ^ 2 + 4y + 16) -4 (y ^ 2 + 4y + 16)\)
Rewriting the expression we have:
\(y^ 3 + 4y ^ 2 + 16y - 4y ^ 2 - 16y - 64\)
Comparing with the given expression we have:
\(y ^ 3 + 4y ^ 2 + ay - 4y ^ 2 - ay - 64 = y ^ 3 + 4y ^ 2 + 16y - 4y ^ 2 - 16y - 64\)
From where we conclude that:
\(a = 16\)
Answer:
The value of a in the polynomial is:
\(a = 16\)