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What is the perimeter of a triangle with points at (−3, 3) , ​ (3, 4) ​ , and ​ (3,-3)​?

Verified Answer :

coliviao

Let A = point (-3,3), B = point (3,4) and C = point (3,-3)

Using the distance formula (google it):

AB^2 = (-3-3)^2 + (3-4)^2
          = 36 + 1
   AB  = square root of 37 units
BC^2 = (3-3)^2 + (4+3)^2
          = 144
    BC = 12 units
AC^2 = (-3-3)^2 + (3+3)^2
          = 36 + 81
    AC = square root of 117 units

Perimeter = AB + BC +AC
                 = root 37 + 12 + root 117
                 = root 37 + 12 + 3 root 13

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