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Which system of equations can be used to solve the following problem?

Each child ticket for a ride costs 2$ , while each adult ticket costs 6$ . if the ride collected a total of 148$ , and 38 tickets were sold , how many of each type of ticket were sold? let c be the number of child tickets and a be the number of adult tickets.

A2a+6c=38

a+c=148

B2c+6a=38

a+c=148

C2c+6a=148

a+c=38

D6c+2a=148

c+a=38

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I hope this helps you

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KONSETON

Hi :)
The answer for your problem is C

Why?
Because content of your task was sayid Each child ticket for a ride costs 2$" and we know that child is called "c" so
2c
now time for adults."while each adult ticket costs 6$"  and adults is called a so :
6a

2c+6a ="if the ride collected a total of 148$"
so
2c+6a=148
And if we summaries all the tickets we receive 38

So the final form 
2c+6a=148
a+c=38

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